Question

a+ b+ c=56...a:b=2r7.....b:c=3r3...aflati numerele

Answer 1

a=2*b +7
b=3*c+3 => c=(b-3)/3 

inlocuim cele doua in prima ecuatie obtinem:

2*b+7 +b+ (b-3)/3 = 56 (inmultim cu 3 atat in dreapta cat si in stanga, pt a scapa de fractie ) =>

=>6*b+21+3b +b-3=168 =>

10*b +18 =168 => 10*b =150 => b=15

cum a =2*b+7 => a=30+7=37

iar c=(b-3)/3 =(15-3)/3 =12/3 =4 

facand proba: a+b+c =37+15+4 =56 (adevarat )