Question

a+b+c= 77, a-b=b-c, c=b/2, a=?, b=?, c=?

Answer 1

a+b+c=77

a-b=b-c

b=2c, deci b-c=2c-c=c=a-b, adica

a=b+c=2c+c=3c si inlocuim in prima relatie:

3c+2c+c=77
6c=77
c=$\frac{77}{6}$

b=2*$\frac{77}{6}$=$\frac{77}{3}$

a=3*$\frac{77}{6}$=$\frac{77}{2}$

Answer 2

a+b+c=77
a-b=b-c=2c-c=c=a-b


c=b/2,b=2c
a=b+c=2c+c=3c
3c+2c+c=77
6c=77
c=77/6
b=2x77/6=77/3
a=3x77/6=77/2