Question

a) d) [-1; 3] 2. Efectuaţi: a) [-3; 5) (3; 8); d) [-3; 4) [1; 6); terminaţi mulţimile: 3) b) (-3; 4) e) (-7; 3] (-2; 5]; (-1; 5); [-3; 5); [2; 5); f) [-3; +∞o) U (-5; 1). c) (-2; 2] f) (-4; 6] [2; 4); [-2; 9). VIII-a​

Answer 1

a) [-3,5)

[-3,5)={x€R|-3≤x<5)

(3,8)

(3,8)={x€R|3<x<8}

b)(-3,4)

(-3,4)={x€R|-3<x<4}

c)(-2,2]

(-2,2]= {x€R|-2<x≤2}

d) [-3,4)= {x€R|-3≤x<4}

[1,6)= {x€R|1≤x<6}

e)(-7,3]= {x€R|-7<x≤3}

(-2,5]= {x€R|-2<x≤5}

(-1,5)= {x€R|-1<x<5}

[-3,5)= {x€R|-3≤x<5)

[2,5)= {x€R|2≤x<5}

f)[-3,+infinit)U(-5,1)={-1,-2,-3...1,2,3...+infinit}

[2,4)= {x€R|2≤x<4}

[-2,9)= {x€R|-2≤x<9}

Answer 2

Răspuns:

Explicație pas cu pas:

[-3,5) = {x∈R|-3≤x<5)

(3,8 )= {x∈R|3<x<8}

(-3,4) = {x∈R|-3<x<4}

(-2,2] = {x∈R|-2<x≤2}

(-3,4] = {x∈R|-3≤x<4}

[1,6) = {x∈R|1≤x<6}

(-7,3] = {x∈R|-7<x≤3}

(-2,5] = {x∈R|-2<x≤5}

(-1,5) = {x∈R|-1<x<5}

[-3,5) = {x∈R|-3≤x<5)

[2,5) = {x∈R|2≤x<5}

[-3,+∞)U(-5,1) = (-5, +∞)

[2,4) = {x∈R|2≤x<4}

[-2,9) = {x∈R|-2≤x<9}