Question

a) Dacă 3ori x+4ori y+5ori z+27=59, determinați 5ori z+3ori x+4ori y.

b)Știind că x-2ori y+13=52, determinați 3ori x-6ori y+1.

Answer 1

5z+3x+4y=59-27
               = 32
b)x-2y=+13=52,
  x-2y=52-13
        =  39
3x-6y+1= 2x39+1
           =  78+1
          =79

Answer 2

a)3x+4y+5z+27=59
3x+4y+5z=59-27
3x+4y+5z=32
5z+3x+4y=32

b)x-2y+13=52
x-2y=52-13
x-2y=39

3x-6y+1=3(x-2y)+1

=3*39+1
=117+1
=118