Question

a) Descompuneti în factori : 4800;540;3060 b)Câți divizorii are fiecare nr

Answer 1

   
[tex]n = \text{numarul de divizori.}\\\\ 4800= 2^6 \times 3 \times 5^2 \\ \Longrightarrow n= (6+1)(1+1)(2+1)= 7\times2\times3 = \boxed{42 \text{ divizori}}\\\\ 540=2^2\times3^3\times5 \\ \Longrightarrow n= (2+1)(3+1)(1+1)= 3\times4\times2 = \boxed{24 \text{ divizori}}\\\\ 3060=2^2 \times 3^2 \times 5 \times 17\\ \Longrightarrow n= (2+1)(2+1)(1+1)(1+1)= 3\times3\times2\times2 = \boxed{36 \text{ divizori}}\\\\ [/tex]