Question

a)determinati numerele naturale x astfel incat fractile 3 supra x si x supra 5 sa fie ambele subunitare.

Answer 1

subunitar numaratorul < numitorul
$\frac{3}{x}$  unde 3<x ⇒x= 4; x=5 ; x=6....x=∞(infinit)
⇒  $\frac{3}{4} ; \frac{3}{5} ; \frac{3}{6} ; \frac{3}{7} ; ... \frac{3}{299} ... \frac{3}{5977} ....$

$\frac{x}{5}$ unde x<5 ⇒ x=4 ; x=3 ;x=2 ; x=1
⇒$\frac{4}{5} ; \frac{3}{5} ; \frac{3}{5} ; \frac{1}{5}$

Answer 2

2/3=subunitara
2/5=subunitara