Question

a) Determinati toate nr. naturale care impartite la 6 dau catul 11 b) Determinati toate nr. care impartite la 9 dau catul 103. c) Determinati toate nr. naturale care impartite la 7 dau catul 32

Answer 1

a)a:6=11 rest n n<6

a=6×11=66

A=6×11+1=67

A=6×11+2=68

A=6×11+3=69

A=6×11+4=70

A=6×11+5=71

b)b:9=103 rest n n<9

B=9×103=927

B=9×103+1=928

B=9×103+2=929

B=9×103+3=930

B=9×103+4=931

B=9×103+4=932

B=9×103+5=933

B=9×103+6=934

B=9×103+7=935

B=9×103+8=936

C)c:7=32 rest n n<7

C=7×32=224

C=7×32+1=225

C=7×32+2=226

C=7×32+3=227

C=7×32+4=228

C=7×32+5=229

C=7×32+6=230