Matematică, întrebare adresată de Adndreia, 9 ani în urmă

a)radical din 7 -3x=x 7
b)3x 5=radical din 3-x
c)2x radical din 34-5x=7
d)radical din 6-4x-x^2=x+4
e)radical din 1+4x-x^2=x-1
f)radical din 2x^2-3x+2=4-x
g)radical din 3x^2+6x+1=7-x
h)5-radical din x-4=4(x-4)
Va rog ajutatima am nevoie urgent (K)

Răspunsuri la întrebare

Răspuns de samsunggenius
1
a)√7−3x=x(7)
3x+2.645751=7x
3x+2.6457517x=7x7x
10x+2.645751=0
10x+2.645751−2.645751=0−2.645751
10x=2.645751
10x/−10=−2.645751/10
x=0.264575
b)
3x(5)√3−x=24.980762*x=24.980762x
c)2x√345x=7
6.661904x=7
6.661904x/6.661904=7/6.661904
x=1.050751
d)
6-4x-x^2=x+4
x^24x+2.44949=x+4
x^24x+2.44949(x+4)=x+4(x+4)
x25x−1.55051=0
x=−b±b24ac/2a
x=(−5)±(−5)24(−1)(−1.5505102572168221)/2(−1)
x=√18.797959/2
x=−4.667830653621998,0.3321693463780022
e)1+4x-x^2=x-1
x^2+4x+1=x−1
x^2+4x+1(x−1)=x−1(x−1)
x^2+3x+2=0
x=−b±b^24ac/2a
x=(3)±(3)^24(−1)(2)/2(−1)
x=−3±√17/2
x=3/2+−1/2√17 or x=3/2+1/217
f)2x^2-3x+2=4-x
1.414214x^23x+2=−x+4
1.414214x^23x+2(−x+4)=−x+4(−x+4)
1.414214x^22x−2=0
x=−b±b^24ac/2a
x=(−2)±(−2)^24(1.4142135623730951)(−2)/2(1.4142135623730951)
x=√15.313708/2.8284271247461903
x=2.090657850852245,0.6764442884791497
g)3x^2+6x+1=7-x
1.732051x^2+6x+1=−x+7
1.732051x^2+6x+1(−x+7)=−x+7(−x+7)
1.732051x^2+7x−6=0
x=−b±b^24ac/2a
x=(7)±(7)^24(1.7320508075688772)(−6)/2(1.7320508075688772)
x=−7±√90.569219/3.4641016151377544
x=0.7265335920760382,4.767985476403418
h)5-√x-4=4(x-4)
√x+1=4x16
√x+1+−1=4x−16+1
√x=4x17
√x/−1=4x−17/1
√x=4x+17
x=(4x+17)^2
x=16x^2136x+289
x−(16x^2136x+289)=16x^2136x+289(16x^2136x+289)
16x2+137x−289=0
x=−b±b^24ac/2a
x=(137)±(137)^24(−16)(−289)/2(−16)
x=−137±√273/32
x=137/32+−1/32√273 or x=137/32+1/32273
x=137/32+−1/32273
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