Question

a) radical36-radical25
b)radical20+radical45-radical80+radical5
c)radical mare 9la a2+12la a2-radical121 
ajutatima,multumes!

Answer 1

a) √36=6 √25=5 6-5=1 c)√9 la a2= 9 12 la a2= 12*12=144 √121=11 9+144-11=153-11=142 b)√20=2√5 ( l-am descompus pe 20 in factori primi si ne a dat √2 la a2* 5 si l am scos pe 2 de sub radical) √45=3√5 √80=4√5 2√5+3√5-4√5+√5=5√5-4√5+√5=√5+√5=2√5 Scuze ca am inceput cu a) c) si apoi b)!