Question

a) ($\frac{2}\sqrt{3}$ + $\frac{3}\sqrt{2}$ ) x 6 - ( $\frac{1}\sqrt{12}$ - $\frac{1}\sqrt{8}$ ) * $\sqrt{24}$ =

Answer 1

$\frac{2\sqrt2+3\sqrt3}{\sqrt6}*6-\frac{\sqrt2-\sqrt3}{\sqrt{24}}*\sqrt{24}=$
$=2\sqrt{12}+3\sqrt{18}-\sqrt2+\sqrt3=$
$=4\sqrt3+9\sqrt2-\sqrt2+\sqrt3=5\sqrt3+8\sqrt2$

Answer 2

[tex]= (\frac{2 \sqrt{3} }{3} + \frac{3 \sqrt{2} }{2})*6 - \frac{ \sqrt{2}- \sqrt{3} }{ \sqrt{24}} * \sqrt{24} \\\\ = \frac{ 4\sqrt{3}+6 \sqrt{2} }{6} * 6 - \sqrt{2} + \sqrt{3} \\\\ = 4\sqrt{3}+6 \sqrt{2} - \sqrt{2} + \sqrt{3}\\\\ = 5 \sqrt{2} + 5 \sqrt{3} [/tex]