Question

a) X-3 >_ 5
b)-x+7<_x+5
c) 2 (x-3) + 7 > 3x
+ 1​

Answer 1

Răspuns:

a)x-3>5<=>x>8 x=(8:+infinit)

b)-x+7<x+5<=>-x-x<-7+5<=>-2x<-3<=>x>2/3 x=(2/3;+infinit)

c)2(x-3)+7>3x+1<=>2x-6+7>3x+1<=>2x-3x>6-7+1<=>-x>0<=>x<0

x=(-infinit;0)