Question

A= {x apartine N* | 36 supra x+3 apartine N​

Answer 1

36/(x+3) ∈ N unde x+3  ∈D36

D36={1,2,3,4,6,9,12,18,36}

Fie x+3 = 1 ⇒ x = -2 ∉ N

x+3 = 2 ⇒ x = -1 ∉ N

x+3 = 3 ⇒ x = 0 ∈ N

x+3 = 4 =⇒ x = 1

x+3 = 6 ⇒ x = 3

x+3 = 9 ⇒ x = 6

x+3 = 12 ⇒ x = 9

x+3 = 18 ⇒ x = 15

x+3 =36 ⇒ x = 33

A={0,1,3,6,9,15,33}

Answer 2

Răspuns:

Explicație pas cu pas:

D₃₆={ 1,2,3,4,6,9,12 , 18 ,36 }.............D₃₆= divizorii lui 36

-

x+3=1

x=1-3

x=-2 ∉ N

-

x+3=2

x= 2-3

x= 1∉N

-

x+3= 3

x= 3-3

x=0∈ N

-

x+3= 4

x=4-3

x=1 ∈N

-

x+3=6

x= 6-3

x=3∈N

-

x+3=9

x= 9-3

x=6 ∈N

-

x+3=12

x=12-3

x= 9∈N

-

-

x+3=18

x= 18-3

x=15∈N

-

x+3= 36

x= 36-3

x=33 ∈ N

x∈{ 0,1,3,6,9 ,15 , 33 }