Question

a1=6 r=(-2) a2, a3, a4, a5=?

Answer 1

$a_{1} = 6$

$r = - 2$

$a_{2} = a_{1} + r = 6 + ( - 2) = 6 - 2 = 4$

$a_{3} = a_{2} + r = 4 + ( - 2) = 4 - 2 = 2$

$a_{4} = a_{3} + r = 2 + ( - 2) = 2 - 2 = 0$

$a_{5} = a_{4} + r = 0 + ( - 2) = 0 - 2 = - 2$