Question

Acest exercițiu. Vă mulțumesc!​

Answer 1

Explicație pas cu pas:

$A_{ABM}=\frac{1}{2} \cdot \bigg|\begin{vmatrix}1 & 2 & 1 \\ 3 & 1 & 1 \\ X_M & Y_M & 1 \\ \end{vmatrix} \bigg|=\frac{1}{2} \cdot |X_M+2Y_M-5| =2\\|X_M+2Y_M-5|=4\\M \in d: x+y+1=0 \iff X_M+Y_M+1=0\\X_M=-1-Y_M\\|-1-Y_M+2Y_M-5|=4\\|Y_M-6|=4 \impli\\Y_M-6=4 \implies Y_M=10, X_M=-11 \implies \boxed{M(-11,10)}\\Y_M-6=-4 \implies Y_M=2, X_M=-3 \implies \boxed{M(-3,2}$