Question

Aceste două exerciți vă rog cu rezolvarea pas cu pas dau coroana.​

Answer 1

Salutare

a) $3*[5^{9}:5^{8}+ (3^{4} -2^{4} *5)^{2015} +8^{7}:16^{5}]$

$3*[5^{9-8} +(81-16*5)^{2015}+2^{3^{7} }:2^{4^{5} } )]\\\\3*[5^{1}+(81-80)^{2015}+2^{21}:2^{20} ]\\\\3*[5+1^{2015} +2^{21-20} ]\\\\3*[5+1+2^{1} ]\\\\3*[6+2]\\\\3*8\\\\24$

b)

$(2^{10}-2^{9} )(2^{9}- 2^{8} )(2^{8} -2^{7} ):2^{24}\\\\(2^{10}* 2^{9}-2^{10} *2^{8}-2^{9} *2^{9}+2^{9} *2^{8})*(2^{8}- 2^{7} ):2^{24}\\\\(2^{10+9}*2^{8}-2^{10+9}* 2^{7}-2^{10+8}* 2^{8}+2^{10+8}* 2^{7}-2^{9+9}* 2^{8}+2^{9+9}* 2^{7}+2^{9+8}* 2^{8}-2^{9+8}* 2^{7}):2^{24}\\\\(2^{19}* 2^{8}-2^{19}* 2^{7}-2^{18}* 2^{8}+2^{18}* 2^{7}-2^{18}* 2^{8}+2^{18}* 2^{7}+2^{17}* 2^{8}-2^{17}* 2^{7} ):2^{24}$

$(2^{27}-2^{26}-2^{26} +2^{25} -2^{26} +2^{25}+ 2^{25}-2^{24} ):2^{24}$

$(2^{27}-3*2^{26} +3*2^{25}-2^{24} ):2^{24}$

Din paranteza dam factor comun pe $2^{24}$

$2^{24}*(2^{3}-3* 2^{2}+3*2^{1}-1 ):2^{24} \\\\(8-3*4+3*2-1)\\\\(8-12+6-1)\\\\1$