Question

Afla c.m.m.d.c.(cel mai mare divizor comun) al numerelor din perechile date , folosind descompunerea in produs de factori perimi: A)108 si 45 B)57 si 38 C)120 si 48 D)42 si 54 E)182 si 42. Va rog ajutati-ma , urgent

Answer 1

a)   108   si 45

108 = 2 × 54 = 2² × 3³

45 = 3² × 5

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c.m.m.d.c al numerelor ( 108  si 45 ) = 3² = 9

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b)   57  si 38

57 = 3 × 19

38 = 2 × 19

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c.m.m.d.c al numerelor 57 si 38 = 19

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c)    120   si 48

120 = 2³ × 3 × 5

48 = 2⁴ x 3

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c.m.m.d.c al numerelor 120 si  48 = 2³ × 3 =24

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d)    42 si 54

42 = 2 × 3 × 7

54 = 2 × 3³

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c.m.m.d.c al numerelor 42 si 54 = 2 × 3 = 6

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e)    182 si  42

182 = 2 × 7 × 13

42 = 2 × 3 × 7

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c.m.m.d.c al numerelor 182 si 42 = 2 × 7 = 14

182  l  2

 91  l  7

 13  l  13

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