Question

Afla necunoscutele:
(9×9-6×6-a)+(13+7×1)=5×10+3
(99-b-3×8)+2×3=8×2+5×10
(6×4+c)-6×4=2×2
(e-5×6+10×5)-50+4×8=42
(96-3×4-5×8)+f-9×7=13
(23-6×3+g)+3×9-8×3-28=34
(3×9+7×h-53)+5×2-(12-4×2)=6×6
8×8-32-(6×i-51)-(40-2×10)=3×3
Exercițiu de cls a Ii ia.

Answer 1

(9*9-6*6-a)+(13+7*1)=5*10+3
( 81-36-a) +( 13+7) =50+3
45-a+20= 53
45-a=53-20
45-a=33
a=45-33
a= 12

(99-b-3*8)+2*3=8*2+5*10
(99-b-24) +6= 16+50
(99-b-24)+6= 66
(99-b-24)=66-6
(99-b-24)=60
99-b=60+24
99-b=84
b=99-84
b=15

(6*4+c)-6*4=2*2
(24+c)-24=4
(24+c)=4+24
24+c=28
c=28-24
c=4

imi pare rau nu mai am baterie pt restul , nu sunt acasa sa- l pun la incarcat.