Question

afla numarul necunoscut


17+81:9-1×2×[(a:7+14:7+2):2-4+2×2]+32-3×8=6+56:8+5​

Answer 1

Greetings!

17+81÷9-1×2×[(a÷7+14÷7+2)÷2-4+2×2]+32-3×8=6+56÷8+5=

17 + 9 - 2 × [( a ÷ 7 + 2 + 2 ) ÷ 2 - 4 + 4 ] + 32 - 24 = 6 + 7 + 5 =

17 + 9 - 2 × [( a ÷ 7 + 2 + 2 ) ÷ 2 - 4 + 4 ] + 32 - 24 = 18

17 + 9 - 2 × [( a ÷ 7 + 2 + 2 ) ÷ 2 - 4 + 4 ] + 32 = 24 + 18

17 + 9 - 2 × [( a ÷ 7 + 2 + 2 ) ÷ 2 - 4 + 4 ] + 32 = 42

17 + 9 - 2 × ( a ÷ 7 + 2 + 2 ) ÷ 2 - 4 + 4 = 42 - 32

17 + 9 - 2 × ( a ÷ 7 + 2 + 2 ) ÷ 2 - 4 + 4 = 10

17 + 9 - 2 × ( a ÷ 7 + 2 + 2 ) ÷ 2 - 4 = 10 - 4

17 + 9 - 2 × ( a ÷ 7 + 2 + 2 ) ÷ 2 - 4 = 6

17 + 9 - 2 × ( a ÷ 7 + 2 + 2 ) ÷ 2 = 6 + 4

17 + 9 - 2 × ( a ÷ 7 + 2 + 2 ) ÷ 2 = 10

17 + 9 - 2 × ( a ÷ 7 + 2 + 2 ) = 10 × 2

17 + 9 - 2 × ( a ÷ 7 + 2 + 2 ) = 20

26 - 2 × ( a ÷ 7 + 2 + 2) = 20

2 × ( a ÷ 7 + 2 + 2) = 26 + 20

2 × ( a ÷ 7 + 2 + 2) = 46

a ÷ 7 + 2 + 2 = 46 ÷ 2

a ÷ 7 + 2 + 2 = 23

a ÷ 7 + 2 = 23 - 2

a ÷ 7 + 2 = 21

a ÷ 7 = 21 - 2

a ÷ 7 = 19

a = 7 × 19

a = 133

Daca te intrebi cum am facut, am rezolvat ce se putea, apoi am folosit metoda mersului invers

Sper ca te-am ajutat!