Question

Afla numarul necunoscut 4×d+39=47,10×e+57=87 ,9×f+62=71 ,h×9-25=20

Answer 1

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Answer 2

4×d+39=47

4×d=47-39

4×d=8

d=8:4

d=2

10×e+57=87

10×e=87-57

10×e=30

e=30:10

e=3

9×f+62=71

9×f=71-62

9×f=9

f=9:9

f=1

h×9-25=20

h×9=20+25

h×9=45

h=45:9

h=5