Question

Afla numarul necunoscut:
48-a=4*8
b-25=49/7
c+68=9*9

Answer 1

48-a=32 a=16
b-25=7 b=32
c+68=81 c=13

Answer 2

$48-a=4*8 \\ 48-a=32 \\ a=48-32 \\ a=16 \\ b-25= \frac{49}{7} \\ b= \frac{49}{7}+25= \frac{49}{7} + \frac{175}{7}=32 \\ c+68=9*9 \\ c+68=81 \\ c=81-68 \\ c=13$