Question

Afla numarul necunoscut: a) (a+23x10):9+4=57x2 b) (a-98:2):7=12x10+3

Answer 1

a) (a+23x10):9+4=57x2

(a+230):9+4=114

(a+230):9=114-4

(a+230):9=110

a+230=110*9

a+230=990

a=990-230

a=760

b) (a-98:2):7=12x10+3

(a-98:2):7=120+3

(a-49):7=123

a-49=7*123

a-49=861

a=861+49

a=910

Answer 2

a) (a+230):9 + 4 = 114

$\frac{a+230}{9} =110$

a + 230 = 990

a = 990 - 230 = 760

b) (a-98:2):7 = 12*10+3

(a-49):7 = 123

$\frac{a-49}{7}=123$

a-49 = 861

a = 910