Question

Afla suma a patru numere naturale impare consecutive, stiind ca suma dintre al doilea si al patrulea numar este 406

Answer 1

a;a+2;a+4;a+6
a+2+a+6 = 406
2×a = 406-8
2×a = 398
a = 398:2
a = 199
a+2 = 201
a+4 = 203
a+6 = 205

199+201+203+205 = 808


a: |___|
b: |___|+2
c: |___|+4
d: |___|+6
b+d+2+6 = 406
b+d= 406-8 = 398 (doua segmente egale)
398:2 = 199 ( un segment)
a = 199
b = 199+2 = 201
c = 199+4 = 203
d = 199+6 = 205

Answer 2

Fie numerele naturale impare consecutive: a, a+2, a+4, a+6⇒
a+a+2+a+4+a+6=4a+12
a+2+a+6=406⇔2a+8=406⇔2a=406-9⇔2a=398⇔a=199⇒4a+12=4*199+12=796+12=808
raspuns: suma numerelor este 808
sper ca te-am ajutat