Question

afla termenii necunoscuți din sirurile de rapoarte egale .​

Answer 1

Răspuns:

Explicație pas cu pas:

a)

1/x = 2/10 = 3/y = z/20

1/x = 2/10 =>  2 x = 10 =>  x = 10/2 => x = 5

2/10 = 3/y =>  2 y = 3×10 =>  y = 30/2 => y = 15

2/10 = z/20 =>  10 z = 2×20 =>  z = 40/10 => z = 4

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b)

x/1 = 3,6/4,8 = 1,8/y = z/5,2

x/1 = 3,6/4,8 => x = (36/10) × ( 10/48) =(36/48)⁽¹²=3/4 =>  x = 0,75

3,6/4,8 = 1,8/y => 3,6y=4,8×1,8⇒ y =8,64/3,6 => y = 2,4

3,6/4,8 = z/5,2 => z = (3,6×5,2)/4,8 =18,72/4,8 => z = 3,9

(36×52)/100  × ( 10/48 ) = (3×13)/10 = 39/10 = 3,9

36/48 = 3/4, iar 52/4 = 13

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c)

9/22,5 = 8/x = 22/y = z/75

9/22,5 = 8/x → produsul mezilor = produsul extremilor

x = (22,5×8)/9 = 180/9 ⇒   x = 20

9/22,5 = 22/y

y = (22,5×22)/9 = 495/9   ⇒ y = 55

9/22,5 = z/75

z = ( 75×9)/22,5 =675/22,5  ⇒ z = 30

675/22,5 = 675 : (225/10) = 675×(10/225) = 30

675 : 225 = 3