Question

afla valoarea lui a din egalitatile . a×14+244=1000, [(a÷9)×7+(102÷2)]-49=58 , 8×a+573÷3-93=210, a×10÷3=4500, 1+1+1+1+1+1×1×1×1×1=1×a, 14+14×2=7×2+2×,.​

Answer 1

Răspuns:

Explicație pas cu pas:

a×14+244=1000

a x 14 = 1000 - 244

a x 14 = 756

a = 756 : 14

a = 54

[(a÷9)×7+(102÷2)]-49=58

[(a÷9)×7+(102÷2)] = 58 + 49

[(a÷9)×7+(102÷2)] = 107

[(a÷9)×7+51 ] = 107

(a÷9)×7 = 107 - 51

(a÷9)×7 = 56

(a÷9) = 56 : 7

a÷9 = 8

a = 8 x 9

a = 72

8×a+573÷3-93=210

8×a+573÷3 = 210 + 93

8×a+573÷3 = 303

8 x a + 191 = 303

8 x a = 303 - 191

8 x a = 112

a = 112 : 8

a = 14

a×10÷3=4500

a x 10 = 4500 x 3

a x 10 = 13500

a = 13500 : 10

a = 1350

1+1+1+1+1+1×1×1×1×1=1×a

1×1×1×1×1 = 1

1+1+1+1+1+1 = 1 x a

6 = 1 x a

a = 6 : 1

a = 6

14+14×2=7×2+2×a      Acesta nu are  necunoscuta . Am presupus ca ar fi ultima .

14+14×2=7×2+2×a

14 + 28 = 14 + 2 x a

42 = 14 + 2 x a

42 - 14 = 2 x a

28 = 2 x a

a = 28 : 2

a = 14