Question

Afla (x+ 2y + z : 2 ) x 3 + 56 daca x : y= 3 rest 4; x : z =2; x + y +z =358

Answer 1

(X+2y+z:2)x3+56=?
X:y=3 rest 4
X:z=2
X+y+z=358

X=yx3+4
z=X:2
3y+4+y+X:2=358
4y+4+X:2=358
8y+8+X=716
8y+3y+4=708
11y=704
y=64
X=64x3+4
X=192+4
X=196
z=196:2
z=98
(196+2x64+98:2)x3+56=
(196+128+49)x3+56
373x3+56=1119+56=1175