Question

aflarea numărului necunoscut clasa a patra. Vă rog mult. De la (f) în colo ca pe restul le-am știut. Vă rog de la f în colo. Dau coroană! ​

Answer 1

f)500-[(16×18-192:f):7+14×5+10]:4×7+9=299

500-[(288-192:f):7+70+10]:4×7=299-9

500-[(288-192:f):7+70+10]:4×7=290

[(288-192:f):7+70+10]:4×7=500-290

[(288-192:f):7+70+10]:4×7=210

[(288-192:f):7+70+10]:4=210:7

[(288-192:f):7+70+10]:4=30

(288-192:f):7+70+10=30×4

(288-192:f):7+70+10=120

(288-192:f):7+70=120-10

(288-192:f):7+70=110

(288-192:f):7=110-70

(288-192:f):7=40

288-192:f=40×7

288-192:f=280

192:f=288-280

192:f=8

f=192:8

f=24

g)6+[15-(8:a×7+7)]×5=8:(1×4)+3×3

6+[15-(8:a×7+7)]×5=8:4+9

6+[15-(8:a×7+7)]×5=2+9

6+[15-(8:a×7+7)]×5=11

[15-(8:a×7+7)]×5=11-6

[15-(8:a×7+7)]×5=5

15-(8:a×7+7)=5:5

15-(8:a×7+7)=1

8:a×7+7=15-1

8:a×7+7=14

8:a×7=14-7

8:a×7=7

8:a=7:7

8:a=1

a=8:1

a=8

h) 4+4×[4+4×(4+h:4)+4]:4=52

4×[4+4×(4+h:4)+4]=52-4

4×[4+4×(4+h:4)+4]=48

4+4×(4+h:4)+4=48:4

4+4×(4+h:4)+4=12

4×(4+h:4)+4=12-4

4×(4+h:4)+4=8

4×(4+h:4)=8-4

4×(4+h:4)=4

4+h:4=4:4

4+h:4=1

h:4=4-1

h:4=3

h=4×3

h=12

i)834-[(6×137-364:i):7+139]:3=751

[(822-364:i):7+139]:3=834-751

[(822-364:i):7+139]:3=83

(822-364:i):7+139=83×3

(822-364:i):7+139=249

(822-364:i):7=249-139

(822-364:i):7=110

822-364:i=110×7

822-364:i=770

364:i=822-770

364:i=52

i=364:52

i=7

j)234+[(88:4+j)-78:6]×23=809

234+[(22+j)-13]×23=809

[(22+j)-13]×23=809-234

[(22+j)-13]×23=575

(22+j)-13=575:23

(22+j)-13=25

22+j=25+13

22+j=38

j=38-22

j=16