Question

aflati 1/2 din 54m 5/6 din42M² 3/ 4 din 16/27l 1/4 din 8/9g​

Answer 1

Răspuns:

Explicație pas cu pas:

$\bf \dfrac{1}{\not2}\cdot \not54~m =\red{27~m}$

$\bf \dfrac{5}{\not6}\cdot \not42~m^2 =5\cdot 7~m^2=\blue{35~m^2}$

$\bf \dfrac{\not3}{\not4}\cdot \dfrac{\not16}{\not27}~\ell =\dfrac{1}{1} \cdot \dfrac{4}{9} ~\ell=\green{\dfrac{4}{9} \ell}$

$\bf \dfrac{1}{\not4}\cdot \dfrac{\not8}{9}~g =\dfrac{1}{1} \cdot \dfrac{2}{9} ~g=\pink{\dfrac{2}{9} g}$

Answer 2

$\it \dfrac{1}{2}\ din\ 54=\dfrac{1}{\not2}\ \cdot \not54\ ^{27}\ =27\\ \\ \\ \dfrac{5}{6}\ din\ 42=\dfrac{5}{\not6}\ \cdot\not42\ ^7=5\cdot7=35\\ \\ \\ \dfrac{3}{4}\ din\ \dfrac{16}{27}=\dfrac{\not3}{\not4}\ \cdot\dfrac{ \not16\ ^4}{\not27\ _9}= \dfrac{4}{9}$

$\it \dfrac{1}{4}\ din\ \dfrac{8}{9}=\dfrac{1}{\not4}\cdot\dfrac{\not8\ ^2}{9}=\dfrac{2}{9}$