Question

Aflati 2 numere naturale stiind ca suma lor este 104 iara daca le inpartim obtinem catul 3 si restul 4.

Answer 1

$a+b=104 \\ a:b=3 \ rest \ 4 \to \boxed{a=3b+4} \\ \\3b+4+b=104 \\4b+4=104 \\ 4b=104-4 \\ 4b=100 |:4\\\boxed{b=25} \\ \\ a+25=104 \\ a=104-20 \\ \boxed{a=79}$

Answer 2

a+b=104
a:b=3 rest4=> a= 3xb+4
3xb+4+b=104
4xb+4=104
4xb=100=> b=25
a=104-b
a=104-25
a=79