Question

aflati 3 nr. nat impare consecutive stiind ca suma lor se imparte la 8 obtinem catul 15 si restul 3

Answer 1

(a+b+c):8=15 rest 3
a+b+c=8x15+3
a+b+c=120+3
a+b+c=123
a+a+2+a+4=123
3a+6=123
3a=123-6
3a=117
a=117:3
a=39
b=39+2
b=41
c=39+4
c=43
proba:39+41+43=80+43=123

Answer 2

x+1+x+3+x+5 ( cele 3 nr )
(x+1+x+3+x+5) :8=15r3
D=impartitor ori C plus rest
x+1+x+3+x+5 =15x8 +3
3x+9=120+3
3x=123-9
3x=114\:3
x=38

Nr sunt : x+1=39
               x+3=41
               x+5=43
BAFTA IN REALIZAREA TEMELOR SPER CA AI INTELES!