Question

aflati 3 numere naturale x,y si z,stiind ca:x+y=56,y+z=88 si x+z=80

Answer 1

x+y=56=> x=56-y
y+z=88=> z=88-y

56-y+88-y=80
56+88-80=2y
64=2y
y=32

x=56-32=24
z=88-32=56