Question

aflati 3numere naturale x,y,z stiind ca :x+y=56,y,+z=88,x+z=80

Answer 1

x+y=56
y+z=88
x+z=80(+)
x=?
y=?
z=?

2(x+y+z)=56+88+80
2(x+y+z)=224
x+y+z=224:2
x+y+z=112

x+y+z=112
x+y=56
z=112-56
z=56

x+y+z=112
y+z=88
x=112-88
x=24

x+y+z=112
x+z=80
y=112-80
y=32

Answer 2

x+y=56
y+z=88
x+z=80

x=56-y
z=88-y

x+z= 56-y+88-y; x+z=80
56-y+88-y= 80
56+88-80=2y
64=2y
y=64:2; y=32
Reluam:
x+y=56; x=56-32; x=24
y+z=88; z=88-32; z=56;
Verificam:
x+z=80
24+56=80