Question

Aflati 4 nr naturale consecutive stiind ca impartind suma lor la 5 obtinem catul 8 si restul 2.

Answer 1

(a+a+1+a+2+a+3)/5=8 si rest 2
4a+6=42
4a=36
a=9
numerele sunt 9,10,11,12

Answer 2

(a+a+1+a+2+a+3):5=8 r 2
(4a+6):5=8 r 2
4a+6=5·8+2
4a+6=40+2
4a+6=42/-6
4a=36/:4⇒a=9
                 a+1=10
                 a+2=11
                 a+3=12
Coroana?:)))