Question

Aflati 4 numere naturale consecutive stiind ca impartind suma lor la 5 obtinem catul 8 si restul 2.

Answer 1

Notam cele 4 numere cu a; a+1; a+2; a+3              
  (a+a+1+a+2+a+3):5=C8 R2 
  (4a+6):5=c8 R2 
  4a+6=8x5+2 
  4a+6=42 I-6 
  4a=36 I:4
  a=9      a+1=10       a+2=11      a+3=12

Answer 2

5×8+2=42
a+a+1+a+2+a+3=42
4a+6=42
4a=42-6
4a=36
a=36:4
a=9
9,10,11,12