Question

aflati a,b,c, daca a/3=b/4=c/8 si 2a+3b+c=520

Answer 1

amplific primul raport cu 2  al doile cu 3 si apoi aplic proprietatea sirului de rapoarte egale 

2a/6=3b/12=c/8==(2a+3b+c)/(6+12+8)=520/26=20


2a/6=20  2a=120  ⇒a=60

3b/12=20 3b=12·20 ⇒b=80

c/8=20  ⇒c=160