Question

Aflati a:
$1 \frac{1}{3}+2 \frac{1}{3}+...+9 \frac{1}{3} =a$

Answer 1

4/3+7/3+10/3+13/3+16/3+19/3+22/3+25/3+28/3=
(4+7+10+13+16+19+22+25+28)/3=
144/3=
48

Answer 2

adunam intregii separat si treimile separat
1+2+3+...9=9(9+1)/2=9*10/2=45
1/3*9=3
45+3=48
sper ca te am ajutat!