Question

aflati ce mai mic numar natural care impartit la 44,22,33 da de fiercare data restul 8

Answer 1

a:44=z rest 8=>a=44z+8=> a-8=44z \
a:22=y rest 8=> a=22y+8=> a-8=22y  | => a-8∈ M₄₄∩M₂₂∩M₃₃
a:33=w rest 8=> a=33w+8=>a-8=33w/

[44,22,33]=2²X3X11=132
a-8∈{132,264,396,528.......} |+8 
RASPUNS a∈{140,272,404,536.....}