Question

Aflati cel mai mic nr . natural , care impartit pe rand la numerele 24 si 58 , da acelasi rest 5 si caturile nenule .

Answer 1

x:24=c1 rest 5
x=M₂₄+5

x:40=c2 rest 5
x=M₄₀ +5

x:58=c3 rest 5
x=M₅₈ +5

x=[M₂₄;M₄₀;M₅₈]+5
x-cel mai mic

24=2³ *3
40=2³ *5
58=2*29

x=2³ * 3 * 5*29 +5

x=8*15*29 +5

x=3480+5
x=3485