Question

Aflati cel mai mic numar natural care impartit pe rand la 8,12 si 30 sa dea restul 3

Answer 1

n : 8 = x rest 3 => n = 8×x + 3

n : 12 = y rest 3 => n = 12×y + 3

n : 30 = z rest 3 => n = 30×z + 3

8 = 2^3

12 = 2^2 × 3

30 = 2 × 3 × 5
____________
cmmmc = 2^3 × 3 × 5 = 120

n = 120 + 3 = 123 (numarul cautat)
___________________________


Verificare:

123 : 8 = 15 rest 3

123 : 12 = 10 rest 3

123 : 30 = 4 rest 3
_______________

Answer 2

8 = 2³

12 = 2²·3

30 = 2·3·5

cmmmc = 2³·3·5 = 120

Numarul va fi 120 + 3 = 123