Question

aflati cel mai mic numar natural care se imparte succesiv la 8 , la 10 si la 15 si de fiecare data se obtin caturi nenule si restul 5

Answer 1

   
Numarul cautat (n) este cmmmc al numerelor 8, 10 si 15 la care adaugam 5.

Descompunem numerele in factori primi:

[tex]8 = 2^3 \\ \\ 10 = 2 \times 5\\\\ 15 = 3 \times 5\\\\ n = 2^3 \times 3 \times 5 + 5 = 120 + 5 = \boxed{125}\\\\ \text{Verificare: }\\\\ 125 : 8 = 15 ~~~rest~5\\\\ 125 : 10 = 12 ~~~rest~5\\\\ 125 : 15 = 8 ~~~rest~5\\\\[/tex]