Question

Aflati citul si restul impartirii numarului natural a la 5 daca

a=24*5+3
a=5*37+2
a=2*3*5+2
a=0*1*2*3*4*5+4
a=6*5
a=8*5+5
a=10*5+20*5
a=10*5-4*5

Answer 1

(24 * 5 + 3) : 5 = 123 : 5 = 24 rest 3
(5 * 37 + 2) : 5 = 37 rest 2
(2 * 3 * 5 + 2) : 5  = 6 rest 2
(0 * 1 * 2 * 3 * 4 * 5 + 4) : 5 =  0 rest 4
(6 * 5) : 5  = 6 rest 0
(8 * 5 + 5) : 5 = 9 rest 0
(10 * 5 + 20 * 5) : 5 = 30 rest 0
(10 * 5 - 4 * 5) : 5 = 6 rest 0