Question

aflati doua numere care au suma 12/5, iar diferenta 0,(3)

Answer 1

Explicație pas cu pas:

$\begin{cases}x + y = \dfrac{12}{5} \\x - y = 0,(3) \end{cases} \iff \begin{cases}x + y = \dfrac{12}{5} \\x - y = \dfrac{3}{9} \end{cases}$

$2x = \dfrac{^{3)} 12}{5} + \dfrac{^{5)} 1}{3} \iff 2x = \dfrac{36 + 5}{15}$

$2x = \dfrac{41}{15} \implies \bf x = \dfrac{41}{30}$

$y = \dfrac{^{6)} 12}{5} - \dfrac{41}{30} = \dfrac{72 - 41}{30} \implies \bf y = \dfrac{31}{30}$