Question

Aflati doua numere naturale consecutive stiind ca impartind triplul unui dintre ele la celalalt numar obtinem catul 2 si restul 5

Answer 1

D=I*c+r                              
3a:b=2 rest 5
3a=2b+5
2b/b+5/b=2 rest 5
2+(5/b)=2 rest 5
5/b=(c+r)/2
$\frac{5}{b}= \frac{c+r}{y2}$

$\frac{5}{b}= \frac{7}{2}$

b=$\frac{5*2}{7} = \frac{10}{7}$

b=10/7

3a=2b+5
3a=20/7+5
21a=20+35
21a=55
a=55/21


daca faci verificarea 

3a=2b+5
3*(55/21)=2*(10/7)+5 =>
55/7=20/7+5   aducem la acelasi numitor
55/7=20/7+7*5
55=20+35