Question

aflati form. moleculara a substantei care contine doi atomi de azot in molecula, 41,48% C si 10,34% hidrogen

Answer 1

in final compusul contine C, H si N

100%-41,48% C - 10,34% H = 48,18% N

C = 41,48/12 = 3,456

H = 10,34/1 = 10,34

N = 48,18/14 = 3,44   : 3,44

=> Fb = CH3N

Fm = (CH3N)n, n = 2 deoarece problema indica 2 at. N

=> Fm = C2H6N2