Question

Aflati m aritmetica ponderata a numerelor: 0,5; 1,12; 3,2 ;4  cu ponderile 3;4;5 si respectiv 8.
b) Calculati:
1.  $\frac{1}{4}$ · { $\frac{1}{4}$ ·[$\frac{1}{4}$ · ( $\frac{1}{4}$ · x +1) +4]+1}+4=5
2.   $\frac{3}{22} x$ - $\frac{1}{2}$ = $\frac{6}{55}$ + $\frac{1}{11}x$

Answer 1

1) map=(0,5 * 3 + 1,12 * 4+ 3,2 * 5 +4*8)/(3+4+5+8)=

=(1,5+4,48+16 +32)/20=

=53,98/20=

=2,699

2) 1/4 * {1/4 * [1/4 * (x/4 +1)+4]+1}=5-4

1/4 * {1/4 * [1/4 *(x+4)/4 +4]+1}=1

1/4 *[(x+4)/16+4]+1=1/1/4

1/4 *(x+4+64)/16+1=1*4/1

(x+70)/16+1=4/1/1/4

(x+70)/16+1=4/1 *4/1

(x+70)/16+1=16

(x+70)/16=16-1

(x+70)/16=15

x+70=15*16

x+70=240

x=240-70

x=170

b)3x/22 -1/2=6/55+x/11

15x/110 -55/110= 12/110 +10x

15x-55=12+10x

15x-10x=12+55

5x=67

x=67/5