Question

Aflati media aritmetica si media geometrica a numerelor a= 2/radical din 2 + 1 si b= radical din (1- radical din 2)^2.​

Answer 1

Răspuns:

$m_a = \sqrt{2}\\\\m_g = 1$

Explicație pas cu pas:

$a = \frac{2}{\sqrt{2}} + 1 = \frac{\sqrt{2}\sqrt{2}}{\sqrt{2}}+1 = \sqrt{2}+1\\\\ b = \sqrt{{(1-\sqrt{2})}^2} = |1 - \sqrt{2}| = \sqrt{2} - 1\\\\ m_a = \frac{a+b}{2} = \frac{\sqrt{2}+1+\sqrt{2}-1}{2} = \frac{2\sqrt{2}}{2} = \sqrt{2}\\\\ m_g = \sqrt{ab} = \sqrt{(\sqrt{2}+1)(\sqrt{2}-1)} = \sqrt{2 - 1} = \sqrt{1} = 1$

Answer 2

a=2/√2 +1=2√2/2+1=√2+1

a=√2+1

b=√(1-√2)²=1-√2

b=√2-1

Ma=√2+1+√2-1/2

Ma=√2

Mg=√(√2+1)(√2-1)

Mg=√2-1

Mg= 1

Succes!