Question

Aflati nr,a,b,c daca axb=45,axc=72,bxc=40

Answer 1

din ab=45⇒b=45/a
din ac=72⇒c=72/a
inlocuim in relatia bc=40⇒    45/a·72/a=40⇒3240/a²=40
40a²=3240
a²=3240/40
a²=81
a=√81
a=9
9b=45⇒b=45/9⇒
b=5
5c=40⇒c=40/5
c=8