Matematică, întrebare adresată de carlashow, 9 ani în urmă

Aflați nr a daca:
repede please

Anexe:

sebyspiderman1: Care puncte???
sebyspiderman1: De la h pana la o??
cocirmariadenis: Frumoase exercitii!

Răspunsuri la întrebare

Răspuns de cocirmariadenis
24
5+[32 - (10:ax4+12)]x7=89
[32 - (10:ax4+12)] x 7 =89 -5
[32 - (10:ax4+12)] x7 =84
32 - (10:ax4+12) = 84 :7
10:ax4+12 = 32 - 12
10:ax4+12=20
10:ax4 = 20 -12
10:a =8:4
10:a=2
a=10:2
a=5

i)
8 - [6400:16- (360-ax2)x5]:20=3
[400- (360-ax2)x5]:20= 8 - 3
[400- (360-ax2)x5]:20=5
400 - (360-ax2)x5= 5x20
400- (360-ax2)x5=100
(360-ax2)x5 = 400 - 100
(360-ax2)x5=300
360-ax2= 300 : 5
360 - ax2=60
ax2=360 - 60
ax2=300
a=300:2
a=150

j)
[ ( 36-46:2x0)+(ax7-3x12)]:7=6
[(36 - 23 x0)+(ax7 - 36)]:7=6
36+(ax7 - 36) = 6x7
ax7-36=42-36
ax7 = 6+36
ax7=42
a=42:7
a=6

k)
5+[90+(20-135:ax3)-54]x6=251
[90+(20-135:ax3)-54]x6=251- 5
[90+(20-135:ax3)-54]x6=246
90+(20-135:ax3)-54=246:6
90+(20-135:ax3)-54=41
90+(20-135:ax3)=41+54
90+(20-135:ax3)=95
20-135:ax3=95-90
20-135:ax3=5
135:ax3=20-5
135:ax3=15
135:a=15:3
135:a=5
a=135:5
a=27

l)
[6x(12:a+56):3-18]x7+78=792
[6x(12:a+56):3-18]x7=792-78
[6x(12:a+56):3-18]x7=714
6x(12:a+56):3-18=714:7
6x(12:a+56):3-18=102
6x(12:a+56):3=102+18
6x(12:a+56):3=120
6x(12:a+56)=120x3
6x(12:a+56)=360
12:a+56=360:6
12:a+56=60
12:a=60-56
a=12:4
a=3

m)
7-[6800:17-5x(360-2xa)]:20 =2
[400-5x(360-2xa)]:20=7-2
[400-5x(360-2xa)]:20 =5
400-5x(360-2xa)=5x20
5x(360-2xa)=400-100
5x(360-2xa)=300
360-2xa=300:5
360-2xa=60
2xa=300
a=150

n)
135+5000:1000+ax44=272
135+5+ax44=272
ax44=272-140
ax44=132
a=3

o)
832:a+[40+8x(20-18)]x10=592
832:a+(40+8x2)x10=592
832:a+56x10=592
832:a=592-560
832:a=32
a=832:32
a=26



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