Question

Aflati nr.abc,stiind ca:a,b(c)+b,c(a)+c,a(b)=2,(2)

Answer 1

$\frac{abc-ab}{90} + \frac{bca-bc}{90} + \frac{cab-ca}{90} = \frac{20}{9}$
$\frac{100a+10b+c-10a+b+100b+10c+a-10b+c+100c+10a+b-10c+a}{90} = \frac{20}{9}$
$\frac{100a+100b+100c}{90} = \frac{20}{9}$
9(100a+100b+100c) = 20*9
9(100a+100b+100c) = 180
100a+100b+100c = 180:9
100a+100b+100c = 20
100(a+b+c) = 20