Question

aflati numarul de forma abc barat care impartite la bc barat dau catul 4 si restul bc barat minus 8.

Answer 1

abc : bc = 4 (restul = bc - 8)
abc = 4×bc + bc - 8
abc = 5×bc - 8
100a + 10b+c = 50b + 5c - 8
100a = 40b + 4c - 8 |:4
25a = 10b + c - 2
10b + c - 25a = 2
10b+c > 25a
ptr b = 2
c = 7
==> 27 - 25a = 2
==> 25a = 27-2
==> 25a = 25
==> a = 1

deci, abc = 127

Verificare:
127 : 27 = 4 rest 19
27 - 8 = 19 (adevarat)