Question

Aflati numarul natural a din egalitatea:10+ {(a-10)x [380+10x (24+24):4]}=1010

Answer 1

10+((a-10)*(380+10*48:4))=1010
10+((a-10)*(380+120))=1010
10+((a-10)*500)=1010
(a-10)*500=1000
a-10=2
a=12

Answer 2

10+ {(a-10)x [380+10x (24+24):4]}=1010

(a-10)x (380+10x48:4)=1010-10

(a-10)x (380+480:4)=1000

(a-10)x (380+120)=1000

(a-10)x 500=1000

a-10=1000:500

a-10=2

a=2+10

a=12


Dacă tu crezi că merit, astept coroana!